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Quantitative Aptitude formula & trick, short cut method to solve – Basic Maths formula

Lets Start with Syllabus, list of topics in Quantitative Aptitude
Section- I Arithmetical Ability

Best Aptitude study materials here -> Aptitude questions and answers
    1. Numbers
    2. H.C.F. & L.C.M. of Numbers
    3. Decimal Fractions
    4. Simplification
    5. Square Roots & Cube Roots
    6. Average
    7. Problems on Numbers
    8. Problems on Ages
    9. Surds & Indices
    10. Percentage
    11. Profit & Loss
    12. Ratio & Proportion
    13. Partnership
    14. Chain Rule
    15. Time & work
    16. Pipes & Cistern
    17. Time & Distance
    18. Problems on Trains
    19. Boats & Streams
    20. Alligation or Mixture
    21. Simple Interest
    22. Compound Interest
    23. Logarithms
    24. Area
    25. Volume & Surface Areas
    26. Races & Games of Skill
    27. Calendar
    28. Clocks
    29. Stocks & Shares
    30. Permutations & Combinations
    31. Probability
    32. True Discount
    33. Banker's Discount
    34. Heights & Distances
    35. Odd Man Out & Series
Section- II Data Interpretation
    36. Tabulation
    37. Bar Graphs
    38. Pie Charts
    39. Line Graphs

      This article about Quantitative aptitude and numerical ability to solve a question in a seconds with the help of basic mathematic formula and tricks contains 70 formulas



      1.A number is divisible by 2, if its unit’s place digit is 0, 2, 4, or 8
      2. A number is divisible by 3, if the sum of its digits is divisible by 3
      3. A number is divisible by 4, if the number formed by its last two digits is divisible by 4
      4. A number is divisible by 8, if the number formed by its last three digits is divisible by 8
      5. A number is divisible by 9, if the sum of its digits is divisible by 9
      6. A number is divisible by 11, if, starting from the RHS,
      (Sum of its digits at the odd place) – (Sum of its digits at even place) is equal to 0 or 11x
      7. (a + b)2 = a2 + 2ab + b2
      8. (a - b)2 = a2 - 2ab + b2
      9. (a + b)2 - (a - b)2 = 4ab
      10. (a + b)2 + (a - b)2 = 2(a2 + b2)
      11. (a2 – b2) = (a + b)(a - b)
      12. (a3 + b3) = (a + b)(a2 - ab + b2)
      13. (a3 – b3) = (a - b)(a2 + ab + b2)
      14. Results on Division:
      Dividend = Quotient × Divisor + Remainder
      15. An Arithmetic Progression (A. P.) with first term ‘a’ and Common Difference ‘d’ is given
      by: [a], [(a + d)], [(a + 2d)], … … …, [a + (n - 1)d]
      nth term,
      Tn = a + (n - 1)d
      Sum of first ‘n’ terms,
      Sn = n/2 (First Term + Last Term)
      16. A Geometric Progression (G. P.) with first term ‘a’ and Common Ratio ‘r’ is given by:
      a, ar, ar2, ar3, … … …, arn-1
      nth term, Tn = arn-1
      Sum of first ‘n’ terms Sn = [a(1 - rn)] / [1 - r]
      17. (1 + 2 + 3 + … … … + n) = [n(n + 1)] / 2
      18. (12 + 22 + 32 + … … … + n2) = [n(n + 1)(2n + 1)] / 6
      19. (13 + 23 + 33 + … … … + n3) = [n2(n + 1)2] / 4


      H.C.F & L.C.M of Numbers solved problems

      Quantitative Apptitude Percentage Solved problem

       Percentage
      32. To express x% as a fraction, we have x% = x / 100
      33. To express a / b as a percent, we have a / b = (a / b × 100) %
      34. If ‘A’ is R% more than ‘B’, then ‘B’ is less than ‘A’ by
      OR
      If the price of a commodity increases by R%, then the reduction in consumption, not
      to increase the expenditure is
      {100R / [100 + R] } %
      35. If ‘A’ is R% less than ‘B’, then ‘B’ is more than ‘A’ by
      OR
      If the price of a commodity decreases by R%, then the increase in consumption, not to
      increase the expenditure is
      {100R / [100 - R] } %
      36. If the population of a town is ‘P’ in a year, then its population after ‘N’ years is
      P (1 + R/100)N
      114 Handy Formulae for Quantitative Aptitude Problems
      Author: Sagar Sonker
      Page 4 of 12
      Copyright © 2006 www.sonker.com
      37. If the population of a town is ‘P’ in a year, then its population ‘N’ years ago is
      P / [(1 + R/100)N]
      Profit & Loss
      38. If the value of a machine is ‘P’ in a year, then its value after ‘N’ years at a depreciation of
      ‘R’ p.c.p.a is
      P (1 - R/100)N
      39. If the value of a machine is ‘P’ in a year, then its value ‘N’ years ago at a depreciation of
      ‘R’ p.c.p.a is
      P / [(1 - R/100)N]
      40. Selling Price = [(100 + Gain%) × Cost Price] / 100
      = [(100 - Loss%) × Cost Price] / 100
      Ratio & Proportion
      41. The equality of two ratios is called a proportion. If a : b = c : d, we write a : b :: c : d and
      we say that a, b, c, d are in proportion.
      In a proportion, the first and fourth terms are known as extremes, while the second and
      third are known as means.
      42. Product of extremes = Product of means
      43. Mean proportion between a and b is
      44. The compounded ratio of the ratios (a : b), (c : d), (e : f) is (ace : bdf)
      45. a2 : b2 is a duplicate ratio of a : b
      46. : is a sub-duplicate ration of a : b
      47. a3 : b3 is a triplicate ratio of a : b
      48. a1/3 : b1/3 is a sub-triplicate ratio of a : b
      49. If a / b = c / d, then, (a + b) / b = (c + d) / d, which is called the componendo.
      50. If a / b = c / d, then, (a - b) / b = (c - d) / d, which is called the dividendo.
      51. If a / b = c / d, then, (a + b) / (a - b) = (c + d) / (c - d), which is called the componendo &
      dividendo.
      52. Variation: We say that x is directly proportional to y if x = ky for some constant k and we
      write, x α y.
      53. Also, we say that x is inversely proportional to y if x = k / y for some constant k and we
      write x α 1 / y.
      114 Handy Formulae for Quantitative Aptitude Problems
      Author: Sagar Sonker
      Page 5 of 12
      Copyright © 2006 www.sonker.com
      Partnership
      54. If a number of partners have invested in a business and it has a profit, then
      Share Of Partner = (Total_Profit × Part_Share / Total_Share)
      Chain Rule
      55. The cost of articles is directly proportional to the number of articles.
      56. The work done is directly proportional to the number of men working at it.
      57. The time (number of days) required to complete a job is inversely proportional to the
      number of hours per day allocated to the job.
      58. Time taken to cover a distance is inversely proportional to the speed of the car.
      Time & Work
      59. If A can do a piece of work in n days, then A’s 1 day’s work = 1/n.
      60. If A’s 1 day’s work = 1/n, then A can finish the work in n days.
      61. If A is thrice as good a workman as B, then:
      Ratio of work done by A and B = 3 : 1,
      Ratio of times taken by A & B to finish a work = 1 : 3
      Pipes & Cisterns
      62. If a pipe can fill a tank in ‘x’ hours and another pipe can empty the full tank in ‘y’ hours
      (where y > x), then on opening both the pipes, the net part of the tank filled in 1 hour is
      (1/x – 1/y)
      Time And Distance
      63. Suppose a man covers a distance at ‘x’ kmph and an equal distance at ‘y’ kmph, then
      average speed during his whole journey is
      [2xy / (x + y)] kmph
      Trains
      64. Lengths of trains are ‘x’ km and ‘y’ km, moving at ‘u’ kmph and ‘v’ kmph (where, u > v) in
      the same direction, then the time taken y the over-taker train to cross the slower train is
      [(x + y) / (u - v)] hrs
      65. Time taken to cross each other is
      [(x + y) / (u + v)] hrs
      66. If two trains start at the same time from two points A and B towards each other and after
      crossing they take a and b hours in reaching B and A respectively.
      Then, A’s speed : B’s speed = ( : ).
      67. x kmph = (x × 5/18) m/sec.
      68. y metres/sec = (y × 18/5) km/hr.
      Boats & Streams
      69. If the speed of a boat in still water is u km/hr and the speed of the stream is v hm/hr,
      then:
      Speed downstream = (u + v) km/hr.
      Speed upstream = (u - v) km/hr.
      70. If the speed downstream is a km/hr and the speed upstream is b km/hr, then:
      Speed in still water = ½ (a + b) km/hr.
      Rate of stream = ½ (a - b) km/hr.

      4 comments :

      Anonymous said...

      informative :)

      Anonymous said...

      For easily solving any question on work and time, one must have clear understanding of concepts. While searching google, I found this page:
      http://learnapti.com/Numerical-Aptitude/Time-and-work.aspx .

      I found this quite useful, so i am sharing this with all of you.

      Unknown said...

      70 formulae?? its better to learn the concepts only and replace those 70 formulae

      Anonymous said...

      You missed 6 in your very first formula...
      1.A number is divisible by 2, if its unit’s place digit is 0, 2, 4, or 8

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